---
### Conclusions
- Relatively simple systems to generate spin-squeezed states in the 1D optical lattice with ultra-cold atoms
- Catalogue of setups with different limitations and advantages
- Novel analysis of squeezing losses due to holes
- Future prospects: large spin, higher dimensions and more complex models
Note:ignored decoherence losses due to temperature, dephasing and losses as they are already in the literature.
---
### Thank you
F. Ferlaino Group
L. Barbiero
---
### Thank you
G. Žlabys
Y. Baamara
M. Dziurawiec
M. Plodzień
A. Niezgoda
M. Mackoit
D. Burba
M. Lewenstein
M. Gajda
A. Sinatra
G. Juzeliūnas
E. Witkowska
---
# Questions from Reviewers
---
### Questions from Reviewers
## Dr. hab. Krzysztof Jachymski
---
**Dipolar interactions in the superfluid regime**
> Could the author comment on [boundary condition effects on the effective model], in particular the expected behaviour for larger numbers of lattice sites?
----
### OBC Effective Model
``
$$
\begin{equation}
\hat{V}_\mathrm{dd} \simeq \frac{\gamma^2}{f_c^2} \left( \zeta(3) - \frac{\zeta(2)}{M} \right)
\left( \tilde{S}^2 - 3 \tilde{S}_x^2 \right)
\end{equation}
$$``
As $f_{c} \le 1$, expect faster dynamics than PBC.
$\zeta(2)/M$ is less relevant.
Expect $f_{c} = 1$ when deep in SF Regime.
----
Expression converges to PBC result
``
$$
\begin{equation}
\hat{V}_\mathrm{dd} \simeq \gamma^2 \zeta(3)
\left( \tilde{S}^2 - 3 \tilde{S}_x^2 \right)
\end{equation}
$$``
----
$J = 10^3 U_{\uparrow\downarrow}$
Going deeper in SF regime reduces oscillations in $f_{c}$.
---
**Dipolar interactions in the superfluid regime**
> A question also arises about the role of the geometry of the system in the rate of entanglement generation, as one could think about using the anisotropy of the dipole interaction and some optimization of the particle alignment.
----
``
$$
\begin{split}
\hat{V}_\mathrm{dd}
=& \frac{1}{8} \sum_{j,k\ne j}
\frac{\gamma^2}{\left| {r}_{jk} \right|^3 }
\Bigg(
4\left( 1-3\cos^2\theta_{jk} \right) \hat{S}^z_j \hat{S}^z_k \\
& -{(1-3\cos^2\theta_{jk})}\left( \hat{S}^+_j\hat{S}^-_k + \hat{S}^-_j\hat{S}^+_k \right) \\
& -{3\sin 2\theta_{jk} e^{-i\phi_{jk}}}\left( \hat{S}^+_j\hat{S}^z_k + \hat{S}^z_j\hat{S}^+_k\right) \\
& -{3\sin 2\theta_{jk} e^{i\phi_{jk}}}\left( \hat{S}^-_j\hat{S}^z_k + \hat{S}^z_j\hat{S}^-_k\right) \\
& -{3}\sin^2\theta_{jk} \left( e^{-i2\phi_{jk}}\hat{S}^+_j\hat{S}^+_k + e^{i2\phi_{jk}}\hat{S}^-_j\hat{S}^-_k \right)
\Bigg)
,\end{split}
$$
``
----
Assume periodic boundary conditions such that ``$\hat{S}^\alpha_j = \tilde{S}_\alpha / \sqrt{M} ; \forall j \in[1, M]$``.
``
$$
\begin{equation}
\begin{split}
\tilde{V}_\mathrm{dd}
=& f \left( 2 \tilde{S}_z^2 - \tilde{S}^2_x - \tilde{S}^2_y \right) { \color{#1f7dad} {\propto 3\tilde{S}_z^2 - \boldsymbol{S}^2 \sim \mathrm{OAT}}}\\
& +\Re[g] \left( \tilde{S}_x\tilde{S}_z + \tilde{S}_z\tilde{S}_x \right) {\color{#53257F} {\sim \mathrm{TACT}}}\\
& +\Im[g] \left( \tilde{S}_y \tilde{S}_z + \tilde{S}_z\tilde{S}_y \right) {\color{#53257F} {\sim \mathrm{TACT}}}\\
& +\Im[h] \left( \tilde{S}_x \tilde{S}_y + \tilde{S}_y\tilde{S}_x \right) {\color{#53257F} {\propto \tilde{S}_+^2 - \tilde{S}_-^2}} \\
& +\Re[h] \left( \tilde{S}_x^2 - \tilde{S}_y^2 \right), {\color{#53257F} {\sim \mathrm{TACT}}}
\end{split}
\end{equation}
$$
``
----
where
``
$$
\begin{align}
f &= \frac{\gamma^2}{4M} \sum_{j\ne k} \frac{1-3\cos^2\theta_{jk}}{\left| {r}_{jk} \right|^3 } \\
g &= -\frac{3\gamma^2}{4M} \sum_{j\ne k} \frac{\sin 2\theta_{jk} e^{i\phi_{jk}}}{\left| {r}_{jk} \right|^3 } \\
h &= -\frac{3\gamma^2}{4M} \sum_{j\ne k} \frac{\sin^2 \theta_{jk} e^{i2\phi_{jk}}}{\left| {r}_{jk} \right|^3 } \\
\end{align}
$$
``
----
Proposed result in Thesis:
``
$$
\begin{align}
f \ne& 0,\\
g =& \Im[h] = 0,\\
\Re[h] =& -3 f.
\end{align}
$$
``
$
\tilde{V}_\mathrm{dd} = 2 f \left(\tilde{S}_z^2 - 2\tilde{S}^2_x + \tilde{S}^2_y \right),
$
----
### Tunable OAT Proposal
``
$$
\begin{align}
f \ne& 0,\\
g =& \Im[h] = 0,\\
\Re[h] =& - \alpha f.
\end{align}
$$
``

$
\tilde{V}_\mathrm{dd} = f \left(2\tilde{S}_z^2 - (1+\alpha)\tilde{S}^2_x - (1-\alpha)\tilde{S}^2_y \right),
$
---
**Spin Orbit Coupling in the Mott regime**
> The dipole interaction naturally generates spin-orbit coupling (omitted by the author, among others, due to the choice of the linear geometry of the system). Could it be used instead of an external laser field?
----
For instance, curved atom chain with optical tweezers.
Possible issues: long-range, mix of interactions
``
$$
\begin{align}
\hat{H} =& - J_0 \sum_{j\ne i}\sum_\sigma \frac{\hat{c}^\dagger_{i\sigma}\hat{c}_{j\sigma}}{|r_{ij}|^3} \\
& - J_2 \sum_{j\ne i} \frac{e^{-2i\phi_{ij}}\hat{c}^\dagger_{i\uparrow}\hat{c}_{j\downarrow} + e^{2i\phi_{ij}}\hat{c}^\dagger_{i\downarrow}\hat{c}_{j\uparrow}}{|r_{ij}|^3}
\end{align}
$$
``
[Syzranov et al, Spin–orbital dynamics in a system of polar molecules, Nat Commun 5, 5391 (2014)](https://www.nature.com/articles/ncomms6391)
Note:It would be possible, but for this same result we would require some curved atom chain in a plane, as relative phase is now encoded in spatial distribution. Optical tweezers are a valid platform.
----
Alternatively, other methods like Floquet engineering

[D. Burba et al, Magnetically generated spin-orbit coupling for ultracold atoms with slowly varying periodic driving, Phys. Rev. A 109 (2024)](https://journals.aps.org/pra/abstract/10.1103/PhysRevA.109.053319)
---
**Spin Orbit Coupling in the Mott regime**
> I would also like to find out why in Formula 6.4 there is a sudden change in the Hamiltonian for the phase equal to pi (the additional material for the article was probably not included in the dissertation) and whether it has any physical significance, because in the experiment the reference phase will probably be of finite accuracy.
----
### Phase $\phi$ under PBC
Eq. 6.4 is stated only for commensurate phases with the lattice ($\phi = 2\pi n / M$), due to periodic boundary conditions.
The sudden change happens because off-diagonal transitions `$\hat{H}_{m,m\pm 2}$` are non-zero only if $\phi = \pi$, while diagonal terms `$\hat{H}_{m,m}$` are always non-zero if $\phi \ne 0$.
----
Detuning would imply broken periodic boundary conditions. Let us assume this is acceptable.
Fist, expand perturbation in spin waves basis
``
$$
\hat{V} | m \rangle \propto c_{m} f_{q} | m+1, q \rangle - c_{-m} (f_{-q})^* | m-1, q \rangle
$$
``
where
$f_{q} = \frac{1}{\sqrt{N}} \sum_{j=1}^N p_{j}^{(q)} \alpha_{j} = \frac{1}{\sqrt{N}} \sum_{j=1}^N e^{i(\phi - \frac{2\pi}{N}q)j - i\phi_{0}} $
----
``
$$
\hat{H}_{\mathrm{eff}} = -2\chi_z\hat{S}_z^2 - 2\chi_x(\hat{S}_x^2 - \hat{S}_y^2) + v_x \hat{S}_x
$$
``
for $\phi_{0} = \phi({M+1})/{2}$
----
where
``
$$
\begin{align}
\chi_z =& \frac{\Omega^2}{4N(N-1)J_\mathrm{SE}}\sum_q\frac{|f_q|^2}{\cos{\frac{2\pi}{N}q} - 1} \\
\chi_x =& \frac{\Omega^2}{4N(N-1)J_\mathrm{SE}}\sum_q\frac{f_q (f_{-q})^*}{\cos{\frac{2\pi}{N}q} - 1} \\
v_x =& \frac{\Omega}{N} \sum_j e^{i\phi j-i\phi_{0}}
\end{align}
$$
``
----
``
$$
\hat{H}_{\mathrm{eff}} = -2\chi_z\left(\hat{S}_z^2 - {\color{#53257F}\eta}\hat{S}_x^2 + {\color{#53257F}\eta}\hat{S}_y^2 + {\color{#1f7dad}\gamma} \hat{S}_x\right)
$$
``
----
### $\phi \sim 2\pi/N$
$N = 8, \Omega = J_\mathrm{SE} (1-\cos 2\pi / N) / 10$
----
### $\phi \sim \pi$
$N = 8, \Omega = J_\mathrm{SE} (1-\cos 2\pi / N) / 10$
---
**Spin Orbit Coupling in the Mott regime**
> What is most surprising to me, however, is the fact that the boundary conditions completely change the evolution of the system.
[...]
, [as] the coupling takes place to a continuous wave spectrum instead of a discrete one. Shouldn't this effect disappear for large system sizes, when the distances between the excited levels decrease?
----
While a continuous spin wave spectrum can be approximated for large $M$, another difference remains:
**the spectrum is still different**.
----
``
$$
\begin{align}
\tilde{S}(q)^+
&\propto \sum_j \cos(\frac{\pi}{M}(j-\frac{1}{2})q) \hat{S}_j^+ \\
&\propto \sum_j (e^{\frac{2\pi}{M}(j-\frac{1}{2})\frac{q}{2}} + e^{-\frac{2\pi}{M}(j-\frac{1}{2})\frac{q}{2}}) \hat{S}_j^+ \\
&\propto \tilde{S}_{PBC}^+(\frac{q}{2}) e^{-\frac{\pi}{M}\frac{q}{2}} + \tilde{S}_{PBC}^+(-\frac{q}{2}) e^{\frac{\pi}{M}\frac{q}{2}} \\
\end{align}
$$
``
---
### Questions from Reviewers
## Prof. Dr. hab. Krzysztof Sacha
---
**Dipolar interactions in the superfluid regime**
> The author rightly points out that the zero-momentum state is not the correct mode to describe atoms [under OBC], but it can be a good approximation. Couldn't the analysis have been performed using the correct modes satisfying open boundary conditions, which are simply a superposition of modes with opposite momenta?
----
``
$$
\begin{align}
\hat{S}_j^\alpha =& \lim_{q\to 0}\sqrt{\frac{2}{N}}\sum_q \cos\left(\frac{2\pi}{N} q j \right) \tilde{S}_q^\alpha \\
\stackrel{?}{\simeq}& \sqrt{\frac{2}{N}} \tilde{S}_{q=0}^\alpha
\end{align}
$$
``
$\chi' \stackrel{?}{\simeq} 2 \chi$
----
$ J = 100U, \eta = 1$
----
Contribution from $q=0$ seems non-trivial.
Proposal: Windowed (short-time) Fourier transform
$X(k,q) = \sum_{j=0}^{N}x_{j} \omega_{j-k} e^{i \frac{2\pi}{N} q j}$
Hann window: $\omega_{j} = \frac{1}{2}\left[1 - \cos\left(\frac{2\pi}{N}j\right)\right]$
---
**Dipolar interactions in the superfluid regime**
> The second question is related to the fact that the atomic losses that may occur in the experiment would be fatal to squeezed states. Three-body recombination coefficients were determined for some elements, and knowing the atomic densities, is it possible to compare how the lifetimes of condensates compare with the times necessary to achieve squeezed states?
----
[D. Kajtoch et al, Spin-squeezed atomic crystal, EPL 123 (2018)](https://iopscience.iop.org/article/10.1209/0295-5075/123/20012/pdf)
---
**Spin Orbit Coupling in the Mott regime**
> The Ph.D. candidate mentions that even if the initial state has double occupancy of the sites, they will be removed as a result of atom collisions. I wonder if this is really possible if in double-occupied sites we only deal with two-body collisions?
----
Inelastic s-wave collisions (losses) between indistinguishable fermions appear experimentally from inhomogeneity of atom-light interactions. P-wave collisions are suppressed, but not forbidden for low temperatures.
[M. Bishof et al, Inelastic collisions and density-dependent excitation suppression in a 87Sr optical lattice clock, Phys. Rev. A 84 (2011)](http://dx.doi.org/10.1103/PhysRevA.84.052716)
[Ch. Lisdat et al, Collisional Losses, Decoherence, and Frequency Shifts in Optical Lattice Clocks with Bosons, Phys. Rev. Lett. 103 (2009)](https://doi.org/10.1103/PhysRevLett.103.090801)
Notes:s-wave collisions for indistinguishable fermions are enabled because the light-atom interaction introduces a degree of inhomogeneity, allowing the fermions to become slightly distinguishable. Furthermore, p-wave collisions, though suppressed at low temperatures, are not forbidden and evidence of p-wave collisions was observed in an optical lattice of fermionic Yb and Sr atoms. The lack of ISB can be attributed to the absence of double occupancy in a single tube due to p-wave inelastic e − e two-body losses (during the relevant experimental time scale).
----
[M. Bishof et al, Inelastic collisions and density-dependent excitation suppression in a 87Sr optical lattice clock, Phys. Rev. A 84 (2011)](http://dx.doi.org/10.1103/PhysRevA.84.052716)
---
**Spin Orbit Coupling in the Mott regime**
> The energy scales resulting from the effective second-order Hamiltonian are extremely small, and consequently spin squeezing requires a very long time evolution. I wonder to what extent the described spin-squeezing can actually be carried out in experiments?
----
Coherence time for bosons ~ 100 ms
[Ilzhöfer et al, Phase coherence in out-of-equilibrium supersolid states of ultracold dipolar atoms, Nat. Phys. 17, 356–361 (2021)](https://doi.org/10.1038/s41567-020-01100-3)
Lifetime for fermions ~ 10-20 s
[Baier et al, Realization of a Strongly Interacting Fermi Gas of Dipolar Atoms, Phys. Rev. Lett. 121, 093602 (2018)](https://journals.aps.org/prl/abstract/10.1103/PhysRevLett.121.093602)
----
$N = 100$
Note:The main experimental constraint is coherence time, in which we can ignore thermal and two-body inelastic collisions. While quite short for bosons, in the order of 100s of ms, we can sustain coherence for fermions in the order of seconds.
----
Nonetheless, the main source for experimental imperfections affecting squeezing seems to be **vacancies in the state preparation**.
---
**Spin Orbit Coupling in the Mott regime**
> Intuition tells me that in the system examined in this dissertation, the key reason for the differences [in boundary conditions results] is the condition imposed on the phase of the laser beam, which can be any for open boundary conditions. [...] I am curious about the Ph.D. candidate’s opinion whether this is really the main reason for the observed differences?
----
As described previously, the main difference is actually the spectrum of the spin wave states
---
# Thank You
---
# Back-up Slides
---
## Coherence of spin wave definitions
$| m, $
$\color{#1f7dad}\pm$
$ q\rangle \propto \pm \sum_{j} (p_{j}^{(q)})^\pm \hat{S}_j^{\pm} | m \mp 1\rangle$
Chosen so that
``$\left(\tilde{S}_{q}^-\right)^\dagger = \tilde{S}_{q}^+$``
----
Under periodic boundary conditions we defined them as
``
$$
| m, q\rangle = \pm c_{{N}/{2}, \pm m }\sum_j e^{\pm i \frac{2\pi}{N} q j} \hat{S}_j^{\pm} | m \mp 1\rangle
$$
``
----
Definition must return exactly the same state with both generators
$|m, q\rangle^\pm = \tilde{S}_{q}^{\pm} |m\mp 1\rangle$
----
``
$$
\begin{align}
|m,q\rangle^+ \propto& \tilde{S}_q^+ \left(\hat{S}^+\right)^{S+m-1}|-S\rangle \\
\propto& \left(\hat{S}^+\right)^{S+m-1}\sum_j p_j^{(q)}|-S\rangle \\
|m,q\rangle^- \propto& \tilde{S}_q^- \left(\hat{S}^+\right)^{S+m+1}|-S\rangle \\
\propto& -\left(\hat{S}^+\right)^{S+m+1}\sum_j \left(p_j^{(q)}\right)^*|-S\rangle \\
\end{align}
$$
``
----
Ignoring this means we need to take ${}^+\langle m, q| m, q'\rangle^- = \delta_{q,-q'}$
We can also choose either
$| m, {\color{#1f7dad}\pm} q\rangle \propto \pm \sum_{j} (p_{j}^{(q)})^\pm \hat{S}_j^{\pm} | m \mp 1\rangle$
or
$| m, q\rangle \propto \pm \sum_{j} {\color{#1f7dad} {p_{j}^{(q)}}} \hat{S}_j^{\pm} | m \mp 1\rangle$
---
### Example Hamiltonian: Two Axis Counter Twisting